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Mathematics

3x2+11x+63=\sqrt{3}x^2 + 11x + 6\sqrt{3} =

  1. (3x+2)(x−33)(\sqrt{3}x + 2)(x - 3\sqrt{3})

  2. (3x+2)(x+33)(\sqrt{3}x + 2)(x + 3\sqrt{3})

  3. (3x−2)(x−33)(\sqrt{3}x - 2)(x - 3\sqrt{3})

  4. (x−2)(x+33)(x - 2)(x + 3\sqrt{3})

Factorisation

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Answer

Given,

⇒3x2+11x+63⇒3x2+9x+2x+63⇒3x(x+33)+2(x+33)⇒(3x+2)(x+33)\Rightarrow \sqrt{3}x^2 + 11x + 6\sqrt{3} \\[1em] \Rightarrow \sqrt{3}x^2 + 9x + 2x + 6\sqrt{3} \\[1em] \Rightarrow \sqrt{3}x(x + 3\sqrt{3}) + 2(x + 3\sqrt{3}) \\[1em] \Rightarrow (\sqrt{3}x + 2)(x + 3\sqrt{3})

Hence, option 2 is correct option.

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