KnowledgeBoat Logo
|

Chemistry

1. ElectrolysisComplete and balance the electrode reactions
a. Electrolysis of fused lead bromide   
1. Dissociation of lead bromidePbBr2 ⇌ …………… + …………… [ions present Pb2+, Br1-] ]
2. Reaction at cathode [inert-graphite]Pb2+ + …………… ⟶ …………… [product Lead metal]
3. Reaction at anode [inert-graphite]Br1- - …………… ⟶ ……………
Br + Br ⟶ …………… [product Bromine vapours]
b. Electrolysis of acidified water   
4. Dissociation of acidified waterH2SO4 ⇌ …………… + ……………
   H2O ⇌ …………… + …………… [ions H1+, SO42-, OH1-]
5. Reaction at cathode [inert-platinum]H1+ + …………… ⟶ ……………
   H + H ⟶ …………… [product Hydrogen gas]
6. Reaction at anode [inert-platinum]OH1- - …………… ⟶ ……………
   4OH ⟶ …………… + …………… [product oxygen gas]
c. Electrolysis of aq. copper sulphate [Active-copper electrode] 
7. Dissociation of aq. copper sulphateCuSO4 ⇌ …………… + …………… [ions present — Cu2+, H1+, SO42-, OH1-]
H2O ⇌ …………… + ……………
8. Reaction at cathode [copper (or Pt. or C)]Cu2+ + …………… ⟶ …………… [product copper metal]
9. Reaction at anode [active copper]Cu - …………… ⟶ …………… [product nil - Cu2+ ions]
[Inert-platinum electrode]
Dissociation of aq. copper sulphate
CuSO4 ⇌ …………… + …………… [ions present — Cu2+, H1+, SO42-, OH1-]
H2O ⇌ …………… + ……………
Reaction at cathode [Pt. or Carbon or Cu]Cu2+ + …………… ⟶ …………… [product copper metal]
Reaction at anode [inert-Pt. or C]OH1- - …………… ⟶ ……………
4OH ⟶ …………… + …………… [product oxygen gas]

Electrolysis

84 Likes

Answer

1. ElectrolysisComplete and balance the electrode reactions
a. Electrolysis of fused lead bromide   
1. Dissociation of lead bromidePbBr2Pb2+ + 2Br1- [ions present Pb2+, Br1-] ]
2. Reaction at cathode [inert-graphite]Pb2+ + 2e-Pb [product lead metal]
3. Reaction at anode [inert-graphite]Br1- - 1e-Br
Br + Br ⟶ Br2 [product Bromine vapours]
b. Electrolysis of acidified water   
4. Dissociation of acidified waterH2SO42H1+ + SO42-
   H2O ⇌ H1+ + OH1- [ions H1+, SO42-, OH1-]
5. Reaction at cathode [inert-platinum]H1+ + 1e-H x 4
   2H + 2H ⟶ 2H2 [product Hydrogen gas]
6. Reaction at anode [inert-platinum]OH1- - 1e-OH x 4
   4OH ⟶ 2H2O + O2 [product oxygen gas]
c. Electrolysis of aq. copper sulphate [Active-copper electrode]
7. Dissociation of aq. copper sulphateCuSO4Cu2+ + SO42- [ions present — Cu2+, H1+, SO42-, OH1-]
H2O ⇌ H1+ + OH1-
8. Reaction at cathode [copper (or Pt. or C)]Cu2+ + 2e-Cu [product copper metal]
9. Reaction at anode [active copper]Cu - 2e-Cu2+ [product nil - Cu2+ ions]
[Inert-platinum electrode]
Dissociation of aq. copper sulphate
CuSO4Cu2+ + SO42- [ions present — Cu2+, H1+, SO42-, OH1-]
H2O ⇌ H1+ + OH1-
Reaction at cathode [Pt. or C or Cu)]Cu2+ + 2e-Cu [product copper metal]
Reaction at anode [inert-pt. or C]OH1- - 1e-OH x 4
4OH ⟶ 2H2O + O2 [product oxygen gas]

Answered By

38 Likes


Related Questions