1 mole of CO₂ occupies 24 dm³ at room temperature and pressure. Calculate the following:

(a) The mass of 6 litres of CO₂.

(b) The volume occupied by 60 g of CO₂.

[Atomic weight: C=12, O=16]

Given:
1 mole of CO₂ occupies 24 dm³ (24 L) at room temperature and pressure

Gram molecular mass of CO₂ = 12 + 2 x 16 = 44 g

(a) 24 litres of CO₂ weighs = 44 g (at room temperature & pressure)

∴ Mass of 6 litres of CO₂ = $\dfrac{44}{24}$ x 6 = 11 g (at room temperature & pressure)

Hence, mass of 6 litres of CO₂ at room temperature & pressure is 11 g.

(b) Volume occupied by 44 g of CO₂ = 24 litres (at room temperature & pressure)

∴ Volume occupied by 60 g of CO₂ = $\dfrac{24}{44}$ x 60 ≈ 32.72 litres (at room temperature & pressure)

Hence, volume occupied by 60 g of CO₂ ≈ 32.72 litres (at room temperature & pressure)