If 1 is a root of the quadratic equation, ky^2 + ky + 3 = 0, then the value of k is: 1. -2/3 2. -1/3 3. -1/2 4. -3/2

Given, 1 is a root of the quadratic equation, ky2 + ky + 3 = 0. Substituting value of y = 1 in equation : ⇒ k(1)2 + k(1) + 3 = 0 ⇒ k + k + 3 = 0 ⇒ 2k + 3 = 0 ⇒ 2k = -3 ⇒ k = . Hence, option 4 is the correct option.

Mathematics

If 1 is a root of the quadratic equation, ky² + ky + 3 = 0, then the value of k is:
$-\dfrac{2}{3}$
$-\dfrac{1}{3}$
$-\dfrac{1}{2}$
$-\dfrac{3}{2}$

Quadratic Equations

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Answer

Given,

1 is a root of the quadratic equation, ky² + ky + 3 = 0.

Substituting value of y = 1 in equation :

⇒ k(1)² + k(1) + 3 = 0

⇒ k + k + 3 = 0

⇒ 2k + 3 = 0

⇒ 2k = -3

⇒ k = $-\dfrac{3}{2}$ .

Hence, option 4 is the correct option.

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Mathematics

If 1 is a root of the quadratic equation, ky² + ky + 3 = 0, then the value of k is:
$-\dfrac{2}{3}$
$-\dfrac{1}{3}$
$-\dfrac{1}{2}$
$-\dfrac{3}{2}$

Quadratic Equations

Answer

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If the roots of the quadratic equation, px(x - 2) + 6 = 0 are equal, then the value of p is:
0
4
6
none of these

If the quadratic equation, px² - $2\sqrt{5}$ px + 15 = 0 has two equal roots, then the value of p is:
0
3
6
both 0 and 3

If the equation x² + 5kx + 16 = 0 has no real roots, then :
k > $\dfrac{8}{5}$
k < $-\dfrac{8}{5}$
$-\dfrac{8}{5} \lt k \lt \dfrac{8}{5}$
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1
2
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