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Mathematics

100 surnames were randomly picked up from a local telephone directory and a frequency distribution of the number of letters in the English alphabet in the surnames was found as follows:

Number of lettersNumber of surnames
1 - 46
4 - 630
6 - 844
8 - 1216
12 - 204

(i) Draw a histogram to depict the given information.

(ii) Write the class interval in which the maximum number of surnames lie.

Statistics

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Answer

  1. It can be observed from the given data that it has class intervals of varying widths.

  2. The proportion of the number of surnames per 2 letters (class interval of minimum class size for reference) can be made.

(i) The length of rectangles are calculated as below:

Number of lettersNumber of surnamesWidth of the classLength of rectangle
1 - 463(6 x 2)/3 = 4
4 - 6302(30 x 2)/2 = 30
6 - 8442(44 x 2)/2 = 44
8 - 12164(16 x 2)/4 = 8
12 - 2048(4 x 2)/8 = 1

Steps of construction :

  1. Take the number of letters on the x-axis using scale 1 block = 1 letter.

  2. Take the proportion of the number of surnames per every 2 letter interval on the y-axis.

  3. To represent our first Head, i.e., (1 - 4) we draw a rectangular bar with width 3 units and length 4 units.

  4. Similarly, other Heads are represented without leaving a gap between two consecutive bars, according to the table.

100 surnames were randomly picked up from a local telephone directory and a frequency distribution of the number of letters in the English alphabet in the surnames was found as follows: NCERT Class 9 Mathematics CBSE Solutions.

(ii) From histogram,

We observe that,

In class interval 6 - 8, 44 surnames lie.

Hence, 6 - 8 is the class interval in which the maximum number of surnames lie.

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