Mathematics
Factorise :
12abc - 6a2b2c2 + 3a3b3c3
Factorisation
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Answer
12abc - 6a2b2c2 + 3a3b3c3
= 3 x 4abc - 3 x 2a2b2c2 + 3a3b3c3
= 3abc(4 - 2abc + a2b2c2)
Hence,12abc - 6a2b2c2 + 3a3b3c3 = 3abc(4 - 2abc + a2b2c2)
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Factorise :
12abc - 6a2b2c2 + 3a3b3c3
4 Likes
12abc - 6a2b2c2 + 3a3b3c3
= 3 x 4abc - 3 x 2a2b2c2 + 3a3b3c3
= 3abc(4 - 2abc + a2b2c2)
Hence,12abc - 6a2b2c2 + 3a3b3c3 = 3abc(4 - 2abc + a2b2c2)
Answered By
3 Likes