If 13 sin θ = 5, find the value of

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13 sin θ = 5 sin θ = sin θ = Let perpendicular = 5x and hypotenuse = 13x By pythagoras theorem, we get : Hypotenuse2 = Base2 + Perpendicular2 Base2 = Hypotenuse2 - Perpendicular2 Base2 = (13x)2 - (5x)2 Base2 = 169x2 - 25x2 Base2 = 144x2 Base = Base = 12x cos θ = tan θ = Substituting values, we get : Hence, .

Mathematics

If 13 sin θ = 5, find the value of

Trigonometrical Ratios

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