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Mathematics

If 16 buffaloes eat as much as 28 cows, how many buffaloes eat as much as 91 cows?

  1. 48
  2. 52
  3. 64
  4. 76

Unitary Method

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Answer

Buffaloes for 28 cows = 16 Buffaloes

Buffaloes for 1 cow = 1628 Buffaloes[Less cows, Less buffaloes]\dfrac{16}{28} \text{ Buffaloes} \quad \text{[Less cows, Less buffaloes]}

Buffaloes for 91 cows = (1628×91) Buffaloes[More cows, More buffaloes]\Big(\dfrac{16}{28} \times 91\Big) \text{ Buffaloes} \quad \text{[More cows, More buffaloes]}

= 47×91 Buffaloes[Dividing 16 and 28 by 4]\dfrac{4}{7} \times 91 \text{ Buffaloes} \quad \text{[Dividing 16 and 28 by 4]}

= 4 x 13 Buffaloes \quad [Dividing 91 and 7 by 7]

= 52 Buffaloes

Hence, option 2 is the correct option.

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