(2 + 3)⁻¹ x (2⁻¹ + 3⁻¹) is equal to : 1. 6 2. -6 3. 1/6 4. -1/6

Given, ⇒ (2 + 3)-1 x (2-1 + 3-1) Hence, option 3 is the correct option.

Mathematics

(2 + 3)^-1 x (2^-1 + 3^-1) is equal to :
6
-6
$\dfrac{1}{6}$
$-\dfrac{1}{6}$

Indices

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Answer

Given,

⇒ (2 + 3)^-1 x (2^-1 + 3^-1)

$\Rightarrow (2 + 3)^{-1} \times (2^{-1} + 3^{-1}) \\[1em] \Rightarrow \Big(\dfrac{1}{5}\Big) \times \Big[\Big(\dfrac{1}{2}\Big) + \Big(\dfrac{1}{3}\Big)\Big]\\[1em] \Rightarrow \dfrac{1}{5} \times \Big[\dfrac{3 + 2}{6}\Big]\\[1em] \Rightarrow \dfrac{1}{5} \times \dfrac{5}{6}\\[1em] \Rightarrow \dfrac{1}{6}.$

Hence, option 3 is the correct option.

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Mathematics

(2 + 3)-1 x (2-1 + 3-1) is equal to :6-616\dfrac{1}{6}61​−16-\dfrac{1}{6}−61​

Indices

Answer

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