Physics
2 kg of ice melts when water at 100° C is poured in a hole drilled in a block of ice. What mass of water was used? Given: Specific heat capacity of water = 4200 J kg-1 K-1, specific latent heat of ice = 336 × 103 J Kg-1.
Calorimetry
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Answer
Given,
mi = 2 kg
Specific heat capacity of water = 4200 J kg-1 K-1,
Specific latent heat of ice = 336 × 103 J Kg-1.
mwater = ?
Since the whole block does not melt and only 2 kg of it melts, so final temperature would be 0° C.
Heat energy taken by ice at 0° C to convert into water at 0° C
= m x L
= 2 × 336000
= 672000 J
Initial temperature of water = 100° C
Final temperature of water = 0° C
Heat energy lost by (mw) kg at 100° C to reach temperature 0° C
= m x c x change in temperature
= m × 4200 × (100 - 0)
= m × 4200 × 100
= 420000 m J
If there is no loss of energy,
heat energy gained = heat energy lost
Substituting the values in the relation above we get,
Hence, mass of water = 1.6 kg
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