Mathematics
2a2 - 18 in the form of factors is :
2(a + 3)(a - 3)
2(a + 1)(a - 9)
2(a - 1)(a - 9)
(2a - 1)(a - 9)
Factorisation
23 Likes
Answer
Given,
2a2 - 18
= 2(a2 - 9)
= 2[(a)2 - (3)2]
= 2(a + 3)(a - 3).
Hence, Option 1 is the correct option.
Answered By
13 Likes
Related Questions
Factorise :
5 - (3a2 - 2a)(6 - 3a2 + 2a)
x4 - 1 in the form of factors is :
(x + 1)(x - 1)(x2 - 1)
(x - 1)(x + 1)(x2 + 1)
(x - 1)(x - 2)(x2 + 2)
(x + 1)(x + 2)(x2 - 1)
27x3 - 48x in the form of factors is :
3(3x - 4)(3x - 4)
3x(3x + 4)(3x + 4)
3(3x2 - 4x)(3x + 4)
3x(3x - 4)(3x + 4)
x2 - (x - 4y)2 in the form of factors is :
8y(x - 2y)
8y(x + 2y)
4y(x + 2y)
4y(x - 2y)