Mathematics
Factorise :
2a2 - 8a - 64
Factorisation
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Answer
2a2 - 8a - 64
= 2(a2 - 4a - 32)
= 2(a2 - (8 - 4)a - 32)
= 2(a2 - 8a + 4a - 32)
= 2[(a2 - 8a) + (4a - 32)]
= 2[a(a - 8) + 4(a - 8)]
= 2(a - 8)(a + 4)
Hence,2a2 - 8a - 64 = 2(a - 8)(a + 4)
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