If 2^(x+1) + 2^x = 3 then 3^x + 3^-3 = 1. 0 2. 1 3. 2 4. 4/3

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KnowledgeBoat · Accepted Answer

Given, 2x + 1 + 2x = 3 Now simplifying: ⇒ 2 × 2x + 2x = 3 ⇒ 2x(2 + 1) = 3 ⇒ 2x × 3 = 3 ⇒ 2x = 1 ⇒ 2x = 20 Equating the exponents: ⇒ x = 0 Substituting value of x in 3x + 3-x, we get : ⇒ 30 + 30 ⇒ 1 + 1 ⇒ 2. Hence, option 3 is the correct option.

Mathematics

If 2^{x + 1} + 2^x = 3, then 3^x + 3^-x =
0
1
2
$\dfrac{4}{3}$

Indices

Answer

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Mathematics

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Indices

Answer

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If 2^{x + 1} + 2^x = 3, then 3^x + 3^-x =
0
1
2
$\dfrac{4}{3}$

If 4^x = 8^y, then x : y =
2 : 3
3 : 2
3 : 4
4 : 3

If (2⁵ + 0.125)² - (2⁵ - 0.125)² = 2^x, then the value of x is :
2
3
4
5

If l^x = m^y = n^z and lmn = 1, then yz + zx + xy =
0
1
-1
$\dfrac{1}{2}$

$\dfrac{9 (4^x)^2}{16^{x + 1} - 2^{x + 1} \times 8^x} =$
0
1
$\dfrac{14}{9}$
$\dfrac{9}{14}$