If 3^x = 3^-x, then (1.2)^x =

1. 0

2. 1

3. 1.2

4. 1.44

Given,

⇒ 3^x = 3^(-x)

$\Rightarrow 3^x = \dfrac{1}{3^x} \\[1em] \Rightarrow 3^x \times 3^x = 1 \\[1em] \Rightarrow 3^{2x} = 1 \\[1em] \Rightarrow 3^{2x} = 3^0 \\[1em]$

Equating the exponents,

$\Rightarrow 2x = 0 \\[1em] \Rightarrow x = 0$

Substituting value of x in (1.2)^x, we get :

⇒ (1.2)⁰

⇒ 1.

Hence, option 2 is the correct option.