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Mathematics

4a2 - (4b2 + 4bc + c2)

Factorisation

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Answer

Given,

   4a2 - (4b2 + 4bc + c2)

= 4a2 - [(2b)2 + 2 × 2b × c + c2]

= (2a)2 - (2b + c)2

= (2a + 2b + c)[2a - (2b + c)]

= (2a + 2b + c)(2a - 2b - c).

Hence, 4a2 - (4b2 + 4bc + c2) = (2a + 2b + c)(2a - 2b - c).

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