Mathematics
Factorise :
4c2 + 3c - 10
Factorisation
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Answer
4c2 + 3c - 10
= 4c2 + (8 - 5)c - 10
= 4c2 + 8c - 5c - 10
= (4c2 + 8c) - (5c + 10)
= 4c(c + 2) - 5(c + 2)
= (c + 2)(4c - 5)
Hence,4c2 + 3c - 10 = (c + 2)(4c - 5)
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Factorise :
4c2 + 3c - 10
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4c2 + 3c - 10
= 4c2 + (8 - 5)c - 10
= 4c2 + 8c - 5c - 10
= (4c2 + 8c) - (5c + 10)
= 4c(c + 2) - 5(c + 2)
= (c + 2)(4c - 5)
Hence,4c2 + 3c - 10 = (c + 2)(4c - 5)
Answered By
2 Likes