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Physics

5 bulbs are connected in series in a room. One bulb is fused. It is removed and remaining 4 bulbs are again connected in series to the same circuit. What will be the effect on the following physical quantities? (Increases, Decreases, Remain Same)

(a) Resistance

(b) Intensity of light

Current Electricity

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Answer

(a) In a series connection, total resistance is the sum of individual resistances.

Let resistance of each bulb be R.

Initially :

Rtotal = 5R

After removing one bulb:

Rtotal = 4R

So, resistance will decrease.

(b) When resistance decreases, total current in the circuit (assuming the same voltage supply) will increase :

I=VR\text I = \dfrac{\text V}{\text R}

So, more current → more power delivered to each bulb.

Since,

Power (P) = I2R,

Hence, intensity of light increases for each remaining bulb.

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