5% pupil in a town died due to some disease and 3% of the remaining left the town. If 2,76,450 pupil are still in the town, find the original number of pupil in the town.

Let the original number of pupil in the town be $x$.

Percentage of pupil died in the town = 5%

Percentage of remaining pupil in the town = (100% - 5%) = 95%

Number of remaining pupil in the town = $\dfrac{95}{100} \times x$

= $\dfrac{19}{20} \times x$

= $\dfrac{19x}{20}$

Percentage of pupil who left the town = 3% of the remaining pupil

Percentage of pupil still in the town = (100% - 3%) = 97% of the remaining pupil

Number of pupil still in the town = 97% of $\dfrac{19x}{20}$

Given, number of pupil still in the town = 2,76,450

∴ 97% of $\dfrac{19x}{20} = 2,76,450$

⇒ $\dfrac{97}{100} \times \dfrac{19x}{20} = 2,76,450$

⇒ $\dfrac{97 \times 19x}{100 \times 20} = 2,76,450$

⇒ $\dfrac{1843x}{2000} = 2,76,450$

⇒ $x = \dfrac{2,76,450 \times 2000}{1843}$

⇒ $x = \dfrac{55,29,00,000}{1843}$

⇒ $x = 3,00,000$

The original number of pupil in the town = 3,00,000.