Given, x + 2 ≤ $\dfrac{x}{3} + 3$ and x is a prime number. The solution set for x is :

1. ∅

2. {0}

3. {1}

4. {0, 1}

If x ≤ -5, x ∈ W

Assertion (A): The above inequation has no solution.

Reason (R): The whole numbers are always positive.

1. Assertion (A) is true, but Reason (R) is false.

2. Assertion (A) is false, but Reason (R) is true.

3. Both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

4. Both Assertion (A) and Reason (R) are correct, and Reason (R) is incorrect reason for Assertion (A).

If -3 ≤ x < $5\dfrac{2}{3}$, x ∈ Z

Assertion (A): x has nine values.

Reason (R): x = 5 is included in the solution set.

1. Assertion (A) is true, but Reason (R) is false.

2. Assertion (A) is false, but Reason (R) is true.

3. Both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

4. Both Assertion (A) and Reason (R) are correct, and Reason (R) is incorrect reason for Assertion (A).

Given below is the graphical representation of an inequality on number line.

Assertion (A): It represents real numbers lying between -5 and $\dfrac{3}{2}$ but not -5 and $\dfrac{3}{2}$.

Reason (R): The hole represents absence of the number -5.

1. Assertion (A) is true, but Reason (R) is false.

2. Assertion (A) is false, but Reason (R) is true.

3. Both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

4. Both Assertion (A) and Reason (R) are correct, and Reason (R) is incorrect reason for Assertion (A).