Factorise :
5ap2 + 11ap + 2a
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= a(5p2 + 11p + 2)
= a(5p2 + (10 + 1)p + 2)
= a(5p2 + 10p + 1p + 2)
= a[(5p2 + 10p) + (1p + 2)]
= a[5p(p + 2) + 1(p + 2)]
= a(p + 2)(5p + 1)
Hence,5ap2 + 11ap + 2a = a(p + 2)(5p + 1)
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