Mathematics
Factorise :
6a2 - 3a2b - bc2 + 2c2
Factorisation
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Answer
6a2 - 3a2b - bc2 + 2c2
= 3a2(2 - b) - c2(b - 2)
= 3a2(2 - b) + c2(2 - b)
= (2 - b)(3a2 + c2)
Hence,6a2 - 3a2b - bc2 + 2c2 = (2 - b)(3a2 + c2)
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Factorise :
6a2 - 3a2b - bc2 + 2c2
8 Likes
6a2 - 3a2b - bc2 + 2c2
= 3a2(2 - b) - c2(b - 2)
= 3a2(2 - b) + c2(2 - b)
= (2 - b)(3a2 + c2)
Hence,6a2 - 3a2b - bc2 + 2c2 = (2 - b)(3a2 + c2)
Answered By
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