Mathematics
Factorise :
6a2 - 3a2b - bc2 + 2c2
Factorisation
10 Likes
Answer
6a2 - 3a2b - bc2 + 2c2
= 3a2(2 - b) - c2(b - 2)
= 3a2(2 - b) + c2(2 - b)
= (2 - b)(3a2 + c2)
Hence,6a2 - 3a2b - bc2 + 2c2 = (2 - b)(3a2 + c2)
Answered By
5 Likes
|
Factorise :
6a2 - 3a2b - bc2 + 2c2
10 Likes
6a2 - 3a2b - bc2 + 2c2
= 3a2(2 - b) - c2(b - 2)
= 3a2(2 - b) + c2(2 - b)
= (2 - b)(3a2 + c2)
Hence,6a2 - 3a2b - bc2 + 2c2 = (2 - b)(3a2 + c2)
Answered By
5 Likes