Mathematics
Factorise :
6xy(a2 + b2) + 8yz(a2 + b2) - 10xz(a2 + b2)
Factorisation
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Answer
6xy(a2 + b2) + 8yz(a2 + b2) - 10xz(a2 + b2)
= (a2 + b2)(6xy + 8yz - 10xz)
= (a2 + b2)2(3xy + 4yz - 5xz)
= 2(a2 + b2)(3xy + 4yz - 5xz)
Hence, 6xy(a2 + b2) + 8yz(a2 + b2) - 10xz(a2 + b2) = 2(a2 + b2)(3xy + 4yz - 5xz)
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