Mathematics
Factorise :
8x2y - 18y3
Factorisation
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Answer
8x2y - 18y3
= 2y (4x2 - 9y2)
= 2y ((2x)2 - (3y)2)
Using the formula
[∵ (x2 - y2) = (x + y)(x - y)]
= 2y (2x - 3y)(2x + 3y)
Hence,8x2y - 18y3 = 2y (2x - 3y)(2x + 3y)
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Factorise :
8x2y - 18y3
6 Likes
8x2y - 18y3
= 2y (4x2 - 9y2)
= 2y ((2x)2 - (3y)2)
Using the formula
[∵ (x2 - y2) = (x + y)(x - y)]
= 2y (2x - 3y)(2x + 3y)
Hence,8x2y - 18y3 = 2y (2x - 3y)(2x + 3y)
Answered By
4 Likes