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Physics

A 9 V battery has an internal resistance of 12 Ω. The potential difference across its terminals when it is supplying a current of 50 mA is

  1. 8.94 V
  2. 8.4 V
  3. 9.06 V
  4. 9.6 V

Current Electricity

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Answer

8.4 V

Reason — Given,

Emf of battery (V) = 9 V

Internal resistance = 12 Ω

Current (I) = 50 mA = 50 x 10-3 A

From formula

V = E - Ir

V = 9 - (50 x 10-3 x 12) = 9 - 0.6 = 8.4 V

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