A bag contains a red ball, a blue ball and a yellow ball, all the balls being of the same size. If a ball is drawn from the bag, without looking into it, find the probability that the ball drawn is :

(i) yellow

(ii) red

(iii) blue

No. of possible outcomes = 3 (1 red + 1 blue + 1 yellow)

(i) No. of yellow balls = 1.

∴ No. of favourable outcomes = 1

P(drawing a yellow ball) = $\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{1}{3}$.

Hence, probability of drawing a yellow ball = $\dfrac{1}{3}$.

(ii) No. of red balls = 1.

∴ No. of favourable outcomes = 1

P(drawing a red ball) = $\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{1}{3}$.

Hence, probability of drawing a red ball = $\dfrac{1}{3}$.

(iii) No. of blue balls = 1.

∴ No. of favourable outcomes = 1

P(drawing a blue ball) = $\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{1}{3}$.

Hence, probability of drawing a blue ball = $\dfrac{1}{3}$.