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Mathematics

A box contains 600 screws, one-tenth are rusted. One screw is taken out at random from this box. Find the probability that it is a good screw.

Probability

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Answer

No. of rusted screws = 110×600\dfrac{1}{10} \times 600 = 60,

No. of good screws = 600 - 60 = 540,

Let E1 be the event of taking out a good screw, then number of favourable outcomes to E1 = 540

P(E1)=No. of favourable outcomes to E1Total no. of possible outcomes=540600=910.P(E1) = \dfrac{\text{No. of favourable outcomes to } E1}{\text{Total no. of possible outcomes}} = \dfrac{540}{600} = \dfrac{9}{10}.

Hence, the probability of taking out a random screw is 910\dfrac{9}{10}.

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