(a + b)2 - a2 + b2
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Given,
= (a + b)2 - (a2 - b2)
= (a + b)2 - (a + b)(a - b)
= (a + b)[(a + b) - (a - b)]
= (a + b)[a + b - a + b]
= 2b(a + b).
Hence, (a + b)2 - a2 + b2 = 2b(a + b).
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a3 - 8 in the form of factors is :
(a - 2)(a2 - 2a + 4)
(a - 2)(a2 + 2a + 4)
(a - 2)(a2 + 2a - 4)
(a + 2)(a2 - 2a + 4)