Physics
(a) Calculate the heat capacity of a copper vessel of mass 200 g if the specific heat capacity of copper is 410 J kg-1 K-1.
(b) How much heat energy will be required to increase the temperature of the vessel in part (a) from 25°C to 35°C?
Answer
(a) Given,
mass (m) = 200 g = 0.20 kg
specific heat capacity (c) = 410 J kg-1 K-1
We know that,
Heat capacity (C') = Mass (m) × specific heat capacity (c)
Substituting the values in the formula above we get,
C' = 0.20 x 410 = 82 J K-1
Hence, heat capacity of a copper vessel = 82 J K-1
(b) Change in temperature = 35°C - 25°C = 10°C = 10 K
Energy required to increase the temperature of vessel Q = ?
From relation,
Q = m x c x △T
Substituting the values in the formula above we get,
Q = 0.20 x 410 x 10 = 820 J
Hence, heat energy required to increase the temperature of the vessel = 820 J
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