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Physics

A car is moving with a speed of 15 km h-1 and another identical car is moving with a speed of 30 km h-1. Compare their kinetic energy.

Work, Energy & Power

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Answer

Speed of first car = 15 km h-1
Speed of second car = 30 km h-1
Mass of both cars = m

Kinetic energy of first car (K1) = 12\dfrac{\text{1}}{\text{2}} x mv2

= 12\dfrac{\text{1}}{\text{2}} x m x (15)2

= 2252\dfrac{\text{225}}{\text{2}} x m

= 112.5 m J

Kinetic energy of second car (K2) = 12\dfrac{\text{1}}{\text{2}} x mv2

= 12\dfrac{\text{1}}{\text{2}} x m x (30)2

= 9002\dfrac{\text{900}}{\text{2}} x m

= 450 m J

Comparing the kinetic energy we get:

K1K2=112.5 m450 m=14\dfrac{\text{K}1}{\text{K}2} = \dfrac{\text{112.5 m}}{\text{450 m}} = \dfrac{\text{1}}{\text{4}}

So Kinetic energy of first car (K1) : Kinetic energy of second car (K2) = 1 : 4.

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