A cistern contains 5 thousand litres of water. If 6% water is leaked, find how many litres of water would be left in the cistern.

Given:

A cistern contains water = 5,000 l

Percentage of water leaked = 6%

Percentage of water retained = (100 % - 6 %) = 94 %

Total water retained = 94 % of 5,000 l

= $\dfrac{94}{100} \times 5,000$

= $\dfrac{4,70,000}{100}$

= 4,700 l

Water left in the cistern would be = 4,700 l