A concave mirror produces three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Where is the image located?

Given, object distance (u) = -10 cm

Magnification = -3 (as the image is real and inverted)

image distance (v) = ?

We know,

$\text{Magnification} = \dfrac{-v}{u} = \dfrac{\text{height of image}}{\text{height of object}} \\[1em]$

Substituting we get,

$-3 = \dfrac{-v}{-10} \\[1em] \Rightarrow -v = (-3) \times (-10) \\[1em] \Rightarrow v = -30 \text{ cm}$

The negative sign indicates that an inverted image is formed in front of the given concave mirror at a distance of 30 cm.