A cylindrical tube open at both ends is made of metal. The internal diameter of the tube is 11.2 cm and its length is 21 cm. The metal thickness is 0.4 cm. Calculate the volume of the metal.
Mensuration
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Question

A cylindrical tube open at both ends is made of metal. The internal diameter of the tube is 11.2 cm and its length is 21 cm. The metal thickness is 0.4 cm. Calculate the volume of the metal.

KnowledgeBoat · Accepted Answer

Internal diameter = 11.2 cm Internal radius = = = 5.6 cm. Thickness = External radius - Internal radius ⇒ 0.4 = External radius - Internal radius ⇒ External radius = 0.4 + Internal radius ⇒ External radius = 0.4 + 5.6 = 6.0 cm Volume of hollow cylinder = π(R² - r²)h, where R = External radius and r = Internal radius. Putting values we get, Hence, volume of metal = 306.24 cm³.

Mathematics

A cylindrical tube open at both ends is made of metal. The internal diameter of the tube is 11.2 cm and its length is 21 cm. The metal thickness is 0.4 cm. Calculate the volume of the metal.

Mensuration

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A cylindrical tube open at both ends is made of metal. The internal diameter of the tube is 11.2 cm and its length is 21 cm. The metal thickness is 0.4 cm. Calculate the volume of the metal.

Mensuration

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