A gaseous hydrocarbon weights 0.70 g. and contains 0.60 g. of carbon. Find the molecular formula of the compound if it's molecular weight is 70. [C = 12, H = 1]
Stoichiometry
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Question

A gaseous hydrocarbon weights 0.70 g. and contains 0.60 g. of carbon. Find the molecular formula of the compound if it's molecular weight is 70. [C = 12, H = 1]

KnowledgeBoat · Accepted Answer

H = 0.70 - 0.60 = 0.1 g Element | % composition | At. wt. |Relative no. of atoms| Simplest ratio --------|---------------|---------|----------------------|---- Carbon | x 100 = 85.71 | 12 | = 7.142 | = 1 Hydrogen | x 100 = 14.28 | 1 | = 14.28 | = 2 Simplest ratio of whole numbers = C : H = 1 : 2 Hence, empirical formula is CH₂ Empirical formula weight = 12 + 2(1) = 14 Molecular weight = 70 Molecular formula = n[E.F.] = 5[CH₂] = C₅H₁₀ Hence, Molecular formula = C₅H₁₀

Chemistry

A gaseous hydrocarbon weights 0.70 g. and contains 0.60 g. of carbon. Find the molecular formula of the compound if it's molecular weight is 70. [C = 12, H = 1]

Stoichiometry

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