A man spent ₹2800 on buying a number of plants priced at ₹x each. Because of the number involved, the supplier reduced the price of each plant by one rupee. The man finally paid ₹2730 and received 10 more plants . Find x.
Quadratic Equations
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Question

A man spent ₹2800 on buying a number of plants priced at ₹x each. Because of the number involved, the supplier reduced the price of each plant by one rupee. The man finally paid ₹2730 and received 10 more plants . Find x.

Quadratic Equations

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KnowledgeBoat · Accepted Answer

In first case, Amount spent = ₹2800 Price of each plant = ₹x No. of plants = In second case, Amount spent = ₹2730 Price of plant is reduced by ₹1 , so new price = ₹(x - 1) Given, in this case 10 more plants were received hence, no. of plants = According to question, Since price cannot be negative hence , x ≠ -20 Hence, the value of x is 14.

Mathematics

A man spent ₹2800 on buying a number of plants priced at ₹x each. Because of the number involved, the supplier reduced the price of each plant by one rupee. The man finally paid ₹2730 and received 10 more plants . Find x.

Quadratic Equations

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