A man's age is three times that of his son and in twelve years he will be twice as old as his son would be. What are their present ages?
Linear Eqns One Variable
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A man's age is three times that of his son and in twelve years he will be twice as old as his son would be. What are their present ages?

KnowledgeBoat · Accepted Answer

Let the age of son be x years. The man's age is three times that of his son, so it equals 3x. In twelve years, he will be twice as old as his son will be, Man's age \+ 12 = 2(son's age \+ 12) ⇒ 3x \+ 12 = 2(x \+ 12) ⇒ 3x \+ 12 = 2x \+ 24 ⇒ 3x \- 2x = 24 \- 12 ⇒ x = 12 Man's age = 3x = 3 12 = 36 Hence, the man's age is 36 years and the son's age is 12 years.

Mathematics

A man's age is three times that of his son and in twelve years he will be twice as old as his son would be. What are their present ages?

Linear Eqns One Variable

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