Physics
A mass of 50 g of a certain metal at 150°C is immersed in 100 g of water at 11°C. The final temperature is 20°C. Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is 4.2 J g-1 K-1.
Calorimetry
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Answer
Given,
Mass of metal (m) = 50 g
Fall in temperature of metal = (150 – 20) = 130°C
Rise in temperature of water = (20 - 11) = 9°C
Heat energy given by metal = mc△t
= 50 x c x 130
= 6500 x c [Equation 1]
Heat energy taken by water = 100 × 4.2 × 9
= 3780 [Equation 2]
Assuming that there is no loss of heat energy,
Heat energy given by metal = Heat energy taken by water.
Equating equations 1 & 2, we get,
Hence, specific heat capacity of the metal = 0.582 J g-1 K-1
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