A number is said to be Armstrong if the sum of cube of its digits is equal to the same number.
For example,
153 = 1³ + 5³ + 3³
Hence, 153 is an Armstrong number.

A program using a class is designed below to check and display whether a number 'num' is an Armstrong number or not. There are some places in the program left blank marked with ?1?, ?2?, ?3? and ?4? to be filled with suitable condition/expression.

class Armstrong { 
    private int num; 
    Armstrong(int n) {
         num = n; 
    boolean check( ) { 
        int nm = num; 
        while(...?1?...) {
            digit = nm % 10; 
            sum = sum + ...?2?... ;
            nm =  ...?3?... ;  
        }
        if (sum == num) 
            return(true); 
        else 
            return(false); 
    } 
    void display( ) {
        boolean ch = check( ); 
        if(ch == ...?4?... ) 
            System.out.println("Number is Armstrong"); 
        else 
            System.out.println("Number is not Armstrong"); 
    }
    }
 }
 

Based on the above discussion, answer the following questions:

(a) What will be filled in place of ?1?

(b) What will be filled in place of ?2?

(c) What will be filled in place of ?3?

(d) What will be filled in place of ?4?

(a) nm > 0

(b) Math.pow(digit,3)

(c) nm / 10

(d) true

The complete program is as follows:

class Armstrong { 
    private int num; 
    Armstrong(int n) {
         num = n; 
    boolean check( ) { 
        int nm = num; 
        while(nm > 0) {
            digit = nm % 10; 
            sum = sum + Math.pow(digit , 3);
            nm = nm / 10 ;  
        }
        if (sum == num) 
            return(true); 
        else 
            return(false); 
    } 
    void display( ) {
        boolean ch = check( ); 
        if(ch == true ) 
            System.out.println("Number is Armstrong"); 
        else 
            System.out.println("Number is not Armstrong"); 
    }
    }
 }