Physics
A piece of stone of mass 15.1 g is first immersed in a liquid and it weighs 10.9 gf. Then on immersing the piece of stone in water, it weighs 9.7 gf. Calculate —
(a) the weight of the piece of stone in air,
(b) the volume of the piece of stone,
(c) the relative density of stone,
(d) the relative density of the liquid.
Related Questions
A jeweller claims that he makes ornament of pure gold of relative density 19.3. He sells a bangle weighing 25.25 gf to a person. The clever customer weighs the bangle when immersed in water and finds that it weighs 23.075 gf in water. With the help of suitable calculations find out whether the ornament is made of pure gold or not.
[Hint — Calculate R.D of material of bangle which comes out to be 11.6]
A piece of iron weighs 44.5 gf in air. If the density of iron is 8.9 x 103 kg m-3, find the weight of the iron piece when immersed in water.
The upthrust is maximum (= FB) when the body is:
- floating in the liquid
- completely immersed inside the liquid
- partially immersed inside the liquid
- None of these
A body weighing W floats partially above and partially below the liquid when (F'B denotes maximum upthrust) :
- W > F'B
- W = F'B
- W < F'B
- none of these