A rectangular swimming pool 20 m long, 10 m wide and 2 m deep is to be tiled. If each tile is 40 cm x 40 cm, find the number of tiles required.

Given:

Length of the swimming pool (l) = 20 m.

Breadth of the swimming pool (b) = 10 m.

Height of the swimming pool (h) = 2 m.

As we know that area of base of the swimming pool = l x b

= 20 x 10 m²

= 200 m²

The area of the four walls of the pool = 2 (l + b) h

= 2 (20 + 10) 2 m²

= 2 x 30 x 2 m²

= 120 m²

Total area of pool = Area of base + Area of four walls

Total area of pool = 200 + 120 m²

= 320 m²

Dimensions of each tile:

Length = 40 cm = 0.4 m

Width = 40 cm = 0.4 m

Area of one tile = Length x Width

= 0.4 x 0.4 m²

= 0.16 m²

Let a be the number of tiles required.

a = $\dfrac{\text{Total area of pool}}{ \text{Area of one tile}}$

⇒ a = $\dfrac{320}{0.16}$

⇒ a = $\dfrac{32000}{16}$

⇒ a = 2,000

Hence, 2,000 tiles are required to tile the pool.