Chemistry
A sample of ammonium nitrate when heated yields 8.96 litres of steam (measured at STP)
NH4NO3 ⟶ N2O + 2H2O
(i) What volume of di nitrogen oxide is produced at the same time as 8.96 litres of steam ?
(ii) What mass of ammonium nitrate should be heated to produce 8.96 litres of steam ? [Relative molecular mass of ammonium nitrate, NH4NO3 is 80]
(iii) Determine the percentage of oxygen in ammonium nitrate [O = 16]
Mole Concept
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Answer
(i) Given,
1 vol. of di nitrogen produced at the same time as 8.96 litres of steam (2 vol)
Hence, Vol of di nitrogen = = 4.48 lit.
Hence, volume of di nitrogen oxide produced = 4.48 lit.
(ii) 2 vol = (2 x 22.4) lit steam is produced from 80 g NH4NO3
∴ 8.96 lit of steam will be produced by x 8.96 = 16 g
Hence, 16 g of ammonium nitrate is required to be heated.
(iii) % of oxygen in ammonium nitrate = x 100 = 60 %
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