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Chemistry

A sample of carbon dioxide occupies 30 cm3 at 15°C and 740 mm pressure. Find its volume at S.T.P.

Gas Laws

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Answer

Initial conditionsFinal conditions [S.T.P.]
P1 = Initial pressure of the gas = 740 mm HgP2 = Final pressure of the gas = 760 mm Hg
V1 = Initial volume of the gas = 30 cm3V2 = Final volume of the gas = ?
T1 = Initial temperature of the gas = 15°C = 15 + 273 = 288 KT2 = Final temperature of the gas = 273 K

By Gas Law:

P1×V1T1=P2×V2T2\dfrac{\text{P}1\times\text{V}1}{\text{T}1} = \dfrac{\text{P}2\times\text{V}2}{\text{T}2}

Substituting the values :

740×30288=760×V2273V2=740×30×273288×760V2=27.68 cm3\dfrac{740 \times 30}{288} = \dfrac{ 760 \times\text{\text{V}}2}{273} \\[1em] \text{V}2 =\dfrac{740 \times 30\times 273}{288 \times 760} \\[1em] \text{V}_2 = 27.68 \text{ cm}^3

∴ Volume of carbon dioxide = 27.7 cm3

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