Chemistry
A sealed tube (able to withstand a pressure of 3 atmospheres) is filled with air at 27°C and one atmosphere pressure. Find the temperature above which it will burst.
Gas Laws
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Answer
P1 = Initial pressure of the gas = 1 atm
T1 = Initial temperature of the gas = 27°C = 27 + 273 = 300 K
P2 = Final pressure of the gas = 3 atm
T2 = Final temperature of the gas = ?
V1 = V2 = V [constant volume]
By Gas Law:
Substituting the values :
∴ The temperature above which the tube will burst is 627°C.
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