Physics

A stone is dropped freely from the top of a tower and it reaches the ground in 4 s. Taking g = 10 m s^-2, calculate the height of the tower.

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From the equation of motion,

h = ut + $\dfrac{1}{2}$ gt²

Given,

g = 10 m s^-2

t = 4 s

u = 0

Substituting the values in the formula, we get,

$h = (0 \times 4) + (\dfrac{1}{2} \times 10 \times 4^2) \\[0.5em] h = 0 + (5 \times 16) \\[0.5em] h = 5 \times 16 \\[0.5em] h = 80 m \\[0.5em]$

Hence, the height of the tower is 80 m

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