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Mathematics

A sum of ₹ 13500 is invested at 16% per annum compound interest for 5 years. Calculate :

(i) the interest for the first year.

(ii) the amount at the end of the first year.

(iii) the interest for the second year, correct to the nearest rupee.

Compound Interest

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Answer

(i) For first year :

P = ₹ 13500

R = 16%

T = 1 year

I = P×R×T100=13500×16×1100\dfrac{P \times R \times T}{100} = \dfrac{13500 \times 16 \times 1}{100} = ₹ 2160.

Hence, interest for first year = ₹ 2160.

(ii) By formula,

Amount = P + I = ₹ 13500 + ₹ 2160 = ₹ 15660.

Hence, amount at end of first year = ₹ 15660.

(iii) For second year :

P = ₹ 15660

R = 16%

T = 1 year

I = P×R×T100=15660×16×1100\dfrac{P \times R \times T}{100} = \dfrac{15660 \times 16 \times 1}{100} = ₹ 2505.6

Hence, interest for second year = ₹ 2506.

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