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Mathematics

A sum of ₹ 20,000 is lent at 12% compound interest compounded yearly. The compound interest accrued in the second year will be :

  1. ₹ 4800

  2. ₹ 288

  3. ₹ 2688

  4. ₹ 5088

Compound Interest

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Answer

For first year :

P = ₹ 20,000

R = 12%

T = 1 year

By formula,

Interest = P×R×T100\dfrac{P \times R \times T}{100}

Substituting values we get :

Interest = 20000×12×1100\dfrac{20000 \times 12 \times 1}{100} = ₹ 2400.

Amount = P + I = ₹ 20,000 + ₹ 2400 = ₹ 22400

For second year :

P = ₹ 22400

R = 12%

T = 1 year

By formula,

Interest = P×R×T100\dfrac{P \times R \times T}{100}

Substituting values we get :

Interest = 22400×12×1100\dfrac{22400 \times 12 \times 1}{100} = ₹ 2688.

Hence, Option 3 is the correct option.

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