A train is moving with uniform speed of 120 km per hour.

(i) How far will it travel in 36 minutes?

(ii) In how much time will it cover 210 km?

(i) Let x km be distance travel in 36 minutes.

Since it is a case of direct variation,

$\therefore \dfrac{120}{60} = \dfrac{x}{36}\\[1em] \Rightarrow x = \dfrac{120 \times 36}{60}\\[1em] \Rightarrow x = \dfrac{4,320}{60}\\[1em] \Rightarrow x = 72$

Hence, the train will travel a distance of 72 km in 36 minutes.

(ii) Let the train take y minutes to cover 210 km.

Since it is a case of direct variation,

$\therefore \dfrac{120}{60} = \dfrac{210}{y}\\[1em] \Rightarrow y = \dfrac{210 \times 60}{120}\\[1em] \Rightarrow y = \dfrac{12,600}{120}\\[1em] \Rightarrow y = 105$

105 minutes = 60 minutes + 45 minutes

= 1 hours 45 minutes

Hence, the train will take 1 hours 45 minutes to cover 210 km.