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A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of 400 m in 20 s. Find its acceleration. Find the force acting on it if it's mass is 7 tonnes.

(Hint: 1 tonne = 1000 kg)

Laws of Motion

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Answer

Given,

Distance (s) = 400 m

Time (t) = 20 sec

Initial velocity (u) = 0

According to the second equation of motion,

S = ut + 12\dfrac{1}{2}at2

Substituting we get,

400 = 0 + 12\dfrac{1}{2} x a x 20 x 20

a = 400×220×20\dfrac{400 \times 2}{20 \times 20} = 2 ms-2

∴ acceleration of the car = 2 ms-2.

Now, mass = 7 tonnes

Converting tonne into kg

1 tonne = 1000 kg

∴ 7 tonnes = 7000 kg

Force = mass x acceleration

F = 7000 x 2 = 14000 N

Hence, Force acting = 14000 N

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