A uniform metre rule of mass 100 g is balanced on a fulcrum at mark 40 cm by suspending an unknown mass m at the mark 20 cm.
(i) Find the value of m.
(ii) To which side the rule will tilt if the mass m is moved to the mark 10 cm?
(iii) What is the resultant moment now?
(iv) How can it be balanced by another mass 50 g?

Question

A uniform metre rule of mass 100 g is balanced on a fulcrum at mark 40 cm by suspending an unknown mass m at the mark 20 cm.
(i) Find the value of m.
(ii) To which side the rule will tilt if the mass m is moved to the mark 10 cm?
(iii) What is the resultant moment now?
(iv) How can it be balanced by another mass 50 g?

KnowledgeBoat · Accepted Answer

(i) As we know, the principle of moments states that Anticlockwise moment = Clockwise moment (ii) When the mass m is shifted to mark 10cm , it results in rule being shifted on the side of mass m in anticlockwise direction. (iii) Anticlockwise moment is produced when a mass of m grams is moved towards the mark of 10cm. Therefore, the resultant moment will be (iv) As we know, the principle of moments states that Anticlockwise moment = Clockwise moment So, Hence, we can balance 50gm at 50cm

Physics

Force

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