A wooden cube of side 10 cm has mass 700 g. What part of it remains above the water surface while floating vertically on the water surface?
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Question

A wooden cube of side 10 cm has mass 700 g. What part of it remains above the water surface while floating vertically on the water surface?

KnowledgeBoat · Accepted Answer

Given, Side of wooden cube = 10 cm Hence, Volume of wooden cube = 10 cm x 10 cm x 10 cm = 1000 cm³ Mass = 700 g By the principle of floatation, Density of water = 1 g cm^-3 Density of wooden cube = 0.7 g cm^-3 Hence, fraction submerged = 0.7 Height of wooden cube = 10 cm Part of woden cube which is submerged = 10 x 0.7 = 7 cm Therefore, part above water = 10 - 7 = 3 cm Hence, 3 cm of height of wooden cube remains above water while floating.

Physics

A wooden cube of side 10 cm has mass 700 g. What part of it remains above the water surface while floating vertically on the water surface?

Fluids Upthrust

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A wooden cube of side 10 cm has mass 700 g. What part of it remains above the water surface while floating vertically on the water surface?

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